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Delhi University MCA Previous Year Questions (PYQs)
Delhi University MCA Time And Work PYQ
Delhi University MCA PYQ
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Delhi University MCA Previous Year PYQDelhi University MCA DU MCA 2019 PYQ
X works twice as fast as Y . Y alone can finish the work in nine days . X and Y together can finish the work in _____ days.
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Delhi University MCA Previous Year PYQDelhi University MCA DU MCA 2019 PYQ
Solution
Delhi University MCA PYQ
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Delhi University MCA Previous Year PYQDelhi University MCA DU MCA 2021 PYQ
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Delhi University MCA Previous Year PYQDelhi University MCA DU MCA 2021 PYQ
Solution
A-------15B-------10
C-------12
Total work (LCM of A,B,C) = 60
Work done by B and C in a day = (6+5)=11
B and C word done in 4 days = 44
Remaining work for A=16
A completes 4 work in a day, so A take 4 more days to complete 16 works.
Delhi University MCA PYQ
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Delhi University MCA Previous Year PYQDelhi University MCA DU MCA 2020 PYQ
A
and B can complete a work in 15 days. B and C can complete the same work in 20
days. If A, B and C together can finish it in 10 days, then A and C can
complete the same work in____days.
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Delhi University MCA Previous Year PYQDelhi University MCA DU MCA 2020 PYQ
Solution
One Day work of A+B = 1/15One Day work of B+C = 1/20
Lwt One Day work of A+C = 1/x
One Day work of A+B+C = 1/10
2.One Day work of A+B+C =(One Day work of A+B)+(One Day work of B+C)+(One Day work of A+C)
$\frac{2}{10}=\frac{1}{15}+\frac{1}{10}+\frac{1}{x}$
x=12
A+C can complete the same work in 12 days.
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